(4/9)^3x-4=(3/2)^2x

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Solution for (4/9)^3x-4=(3/2)^2x equation: 



(4/9)^3x-4=(3/2)^2x

We move all terms to the left:

(4/9)^3x-4-((3/2)^2x)=0



Domain of the equation: 9)^3x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)^2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/9)^3x-((+3/2)^2x)-4=0

We calculate fractions


8^2x)/9^3x*2)^2x))+(-27^3x/9^3x*2)^2x))-4=0

We can not solve this equation

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